Traverse Square Matrix - Spiral Clockwise

Traverse Square Matrix - Spiral Clockwise 

A square matrix of size N*N is provided. The program must traverse the matrix spirally and print the elements in a single line.

Input Format:
The first line contains N.
Next N lines, contain N column values C(i,j) each separated by a space.

Output Format:
The first line contains N*N values separated by a space.

Boundary Conditions:
2 <= N <= 100
0 <= C(i,j) <= 9999

Example Input/Output 1:
Input:
2
1 2
3 4

Output:
1 2 4 3

Example Input/Output 2:
Input:
4
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16

Output:
1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10

Example Input/Output 3:
Input:
5
2 7 7 7 9
10 2 4 2 10
2 9 4 9 2
7 15 10 14 10
12 9 15 12 2

Output:
2 7 7 7 9 10 2 10 2 12 15 9 12 7 2 10 2 4 2 9 14 10 15 9 4

Code:

#include <iostream>

using namespace std;

int main(int argc, char** argv)

{

int n,i,j,k;

cin>>n;

int arr[n][n];

for(i=0;i<n;i++)

    for(j=0;j<n;j++)

        cin>>arr[i][j];

for(i=n-1,j=0;i>0;i--,j++)

    {

        for(k=j;k<i;k++)//top row

            cout<<arr[j][k]<<" ";

        for(k=j;k<i;k++)//last column

            cout<<arr[k][i]<<" ";

        for(k=i;k>j;k--)//last row

            cout<<arr[i][k]<<" ";

        for(k=i;k>j;k--)//first column

            cout<<arr[k][j]<<" ";

    }

   

    int m=(n-1)/2;

    if(n%2==1)

        cout<<arr[m][m];

}

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