Efficient way for Matrix Transpose

                           Matrix Transpose             

                        

Given a matrix of R rows and C columns as the input, the program must print the transpose of the input matrix.

Input Format:
The first line contains R and C separated by a space.

Output Format:
C lines containing R values each, with the values separated by a space.

Boundary Conditions:
1 <= R, C <= 1000

Example Input/Output 1:
Input:
4 3
62 9 88
72 81 31
3 99 72
3 64 51

Output:
62 72 3 3
9 81 99 64
88 31 72 51

Example Input/Output 2:
Input:
3 3
1 2 3
4 5 6
7 8 9

Output:
1 4 7
2 5 8

3 6 9 

Code:

#include <iostream>

using namespace std;

int main(int argc, char** argv)

{

    int i,j,r,c;

cin>>r>>c;

int arr[r][c];

for(i=0;i<r;i++)

    for(j=0;j<c;j++)

        cin>>arr[i][j];     

for(i=0;i<c;i++)

    {

        for(j=0;j<r;j++)

            {

                cout<<arr[j][i]<<" ";

            }

            cout<<"\n";

    }

}

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