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Tuesday, 15 August 2017

Two Policemen Catching a Thief

                   Two Policemen Catching a Thief


                                               
Policeman1 and Policeman2 along with a thief are standing on X-axis. The integral value of their location on the X-axis is passed as the input.
Both the policemen run at the same speed and they start running at the same time to catch the thief.
- The program must print Police1 if Policeman1 will catch the thief first.
- The program must print Police2 if Policeman2 will catch the thief first.
- The program must print Both if Policeman1 and Policeman2 will reach the thief at the same time.
Input Format:
The first line will contain the value of N which represents the number of test cases to be passed as the input.
Next N lines will contain the integral location of Policeman1, Policeman2 and the thief each separated by a space.
Output Format:
The first line will contain one of the following values - Police1, Police2, Both
Constraints:
1 <= N <= 20
Example Input/Output 1:
Input:
3
1 2 3
1 3 2
2 1 3
Output:
Police2
Both
Police1
Example Input/Output 1:
Input:
2
-2 2 0
10 5 -1
Output:
Both
Police2


Code:

#include <iostream>
#include<stdlib.h>
using namespace std;
int main(int argc, char** argv)
{
int n,p1,p2,t,i;
cin>>n;
for(i=0;i<n;i++)
{
    cin>>p1>>p2>>t;
    if(abs(p1-t)>abs(p2-t))
        cout<<"Police2\n";
    else if(abs(p1-t)<abs(p2-t))
        cout<<"Police1\n";
    else
        cout<<"Both\n";
}
}

 Please do comment If u have any Queries!

3 comments:

  1. int n=sc.nextInt();
    int i;
    sc.nextLine();
    String s[]=new String[n];
    for(i=0;isubb1)
    {
    System.out.println("Police2");
    }
    else if(subb1>subb)
    {
    System.out.println("police1");
    }
    else if(subb==subb1)
    {
    System.out.println("BOTH");
    }
    }

    }

    }

    ReplyDelete
  2. int n=sc.nextInt();
    int i;
    sc.nextLine();
    String s[]=new String[n];
    for(i=0;isubb1)
    {
    System.out.println("Police2");
    }
    else if(subb1>subb)
    {
    System.out.println("police1");
    }
    else if(subb==subb1)
    {
    System.out.println("BOTH");
    }
    }

    }

    }

    ReplyDelete
  3. #include
    #include

    int main()
    {
    int n,i,p1,p2,t;
    scanf("%d",&n);
    for(i=0;iabs(p2-t))
    {
    printf("\nPolice2");
    }
    else if(abs(p1-t)<abs(p2-t))
    {
    printf("\nPolice1");
    }
    else
    {
    printf("\nBoth");
    }
    }
    return 0;
    }

    ReplyDelete

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