Day 7: Arrays
Objective
Today, we're learning about the Array data structure. Check out the Tutorial tab for learning materials and an instructional video!
Today, we're learning about the Array data structure. Check out the Tutorial tab for learning materials and an instructional video!
Task
Given an array, , of integers, print 's elements in reverse order as a single line of space-separated numbers.
Given an array, , of integers, print 's elements in reverse order as a single line of space-separated numbers.
Input Format
The first line contains an integer, (the size of our array).
The second line contains space-separated integers describing array 's elements.
The second line contains space-separated integers describing array 's elements.
Constraints
- , where is the integer in the array.
Output Format
Print the elements of array in reverse order as a single line of space-separated numbers.
Sample Input
4
1 4 3 2
Sample Output
2 3 4 1
Code:
C++:
#include <algorithm>
#include <iostream>
using namespace std;
int main() {
int N;
cin >> N;
int arr[N];
for (int i = 0; i < N; i++) {
cin >> arr[i];
}
reverse(arr, arr + N);
for (int i = 0; i < N; i++) {
cout << arr[i] << "
";
}
return 0;
}
Java:
import
java.util.Scanner;
public
class Solution {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
int[] arr = new int[n];
for (int i = 0; i < n; i++) {
arr[i] = in.nextInt();
}
for (int i = 0; i < n; i++) {
int idx = n - i - 1;
System.out.print(arr[idx] + "
");
}
in.close();
}}
Python:
input()
arr =
str(input()).split(" ")
arr.reverse()
for num in arr:
print(num + " ",
end="")
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