Minimum Distance Between Alphabets
Given a string S and two alphabets C1 and C2 present in S, find the minimum distance D between C1 and C2 in S.
Input Format:
The first line will contain S.
The second line will contain C1 and C2 separated by a space.
The first line will contain S.
The second line will contain C1 and C2 separated by a space.
Output Format:
The first line will contain D.
The first line will contain D.
Boundary Conditions:
2 <= Length of S <= 100
2 <= Length of S <= 100
Example Input/Output 1:
Input:
spaceship
c s
Input:
spaceship
c s
Output:
1
Code:1
C++:
#include <iostream>
using namespace std;
int main(int argc, char**
argv)
{
string s;
cin>>s;
char a,b;
cin>>a;
cin>>b;
int
m=s.length(),flag=0,d=0;
for(int
i=0;i<s.length();i++)
{
if(s[i]==a||s[i]==b)
{
if(flag==1&&d!=0)
{
if(d<m)
m=d;
d=0;
}
else
flag=1;
}
if(flag==1)
d++;
}
cout<<m-1;
}
Java:
import java.util.*;
import java.lang.*;
public class Hello {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
String str=sc.next();
char a=sc.next().charAt(0);
char b=sc.next().charAt(0);
int d1=str.indexOf(a);
int d2=str.indexOf(b);
int ld1=str.lastIndexOf(a);
int ld2=str.lastIndexOf(b);
int diff=Math.abs(d1-d2);
int diff1=Math.abs(ld1-ld2);
if(diff<diff1)
System.out.print(diff-1);
else
System.out.print(diff1-1);
}
}
Small logic change is there!!
Please do comment If u have any Queries!
import java.util.*;
ReplyDeletepublic class Hello {
public static void main(String[] args) {
//Your Code Here
Scanner scan=new Scanner(System.in);
String a=scan.next();
char x=scan.next().charAt(0);
char y=scan.next().charAt(0);
int n=0,m=0,o=0,p=0,c=0;
for(int i=0;i=0;i--)
{
if(y==a.charAt(i))
{
m=i;
break;
}
}
if(n>m)
{
o=n;
p=m;
}
else{
o=m;
p=n;
}
for(int i=p+1;i<o;i++)
{
c++;
}
System.out.print(c);
}
}
#include
ReplyDelete#include
#include
#include
#include
using namespace std;
int main(int argc, char** argv)
{
char s[100];
cin>>s;
char a,b;
cin>>a>>b;
int i,i1,j=0,k=0,n=strlen(s);
int ind_a[100],ind_b[100];
for(i=0;iabs(ind_a[i]-ind_b[i1]-1))
//min=
min[x++]=abs(abs(ind_a[i]-ind_b[i1])-1);
//cout<<min[x-1];
}
}
sort(min,min+x);
cout<<min[0];
}
//2 test cases failed out of 7