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Friday, 8 September 2017

String Zig Zag Pattern


                               String Zig Zag Pattern




Given a string S and an integer N as the input, the program must split the string into groups whose size is N and print them as the output in separate lines in a zig zag manner. If the last group size is less than N then the remaining letters must be filled with asterisk as shown in the Example Input/Output.
Input Format:
The first line contains S.
The second line contains N.
Output Format:
LENGTH(S)/N + LENGTH(S)%N lines containing the desired pattern.
Boundary Conditions:
4 <= LENGTH(S) <= 500
2 <= N <= LENGTH(S)
Example Input/Output 1:
Input:
ENVIRONMENT
3
Output:
ENV
ORI
NME
*TN
Example Input/Output 2:
Input:
ENVIRONMENT
4
Output:
ENVI
MNOR
ENT*
Example Input/Output 3:
Input:
EVERYDAY
2
Output:
EV
RE
YD
YA

Example Input/Output 4:
Input:

DEOCTULWBDTMYGKWSMFNWDQIMOGINKKUHHLWTEYLCXFSMODZX
14


Output:

DEOCTULWBDTMYG
IGOMIQDWNFMSWK
NKKUHHLWTEYLCX
*******XZDOMSF


Code:

Java:

import java.util.*;
public class Hello {

    public static void main(String[] args) {
                   Scanner sc=new Scanner(System.in);
          String str=sc.next();
          String temp;
          int n=sc.nextInt(),k=0,i,j,len=0;
          int l=str.length();
    while(l%n!=0)
        {
            str+='*';
            l=str.length();
        }
    for(i=n;i<=str.length();i+=n)
    {
        temp=str.substring(len,i);
        StringBuffer sb=new StringBuffer(temp);
        if(k%2==0)
            System.out.println(temp);
        else 
               System.out.println(sb.reverse());

        len+=n;
        k++;
    }
          }
}

C++program:

#include <iostream>
using namespace std;
int main(int argc, char** argv)
{
string s;
int n,c=0,l;
cin>>s;
cin>>n;
l=s.length();
while(l%n!=0)
{
s.append("*");
l=s.length();
}
int i=0,t=0;
while(i<l)
    {
    cout<<s[i];
    c++;
    if(c==n)
    {
    c=0;
    cout<<"\n";
    i=i+n;
    t++;
    }
    else
    {
    if(t%2==0)
    i++;
    else
    i--;
    }
}
}

Please do comment If u have any Queries!

3 comments:

  1. superb code bro

    ReplyDelete

  2. a,n,l=input().strip(),int(input()),0
    if(len(a)%n==0):
    l=len(a)//n
    else:
    l=(len(a)//n)+1
    a,k=a+("*"*10),0
    for i in range(0,l):
    if(i%2==0):
    print(a[k:k+n])
    k=k+n
    else:
    k=k+n-1
    print(a[k:k-n:-1])
    k=k+1

    ReplyDelete

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